The+Double+KS's

Kimmy and Kayla S. Hour 3 Second Quarter Project

[[image:MIDPOINTSSSS.jpg width="800" height="600"]]
AD: (-4+0/2)=-2 (-2+2/2)=0 DG: (0+3/2)=1.5 (2+-3)=-.5
 * (-2,0)** is the midpoint for AD and is labled as point O
 * (1.5,-.5)** is the midpoint for DG and is labled as point K

These are the slopes, perpendicular bisectors, circumcenter point, and radius length of triangle ADG.


The perpendicular bisector for AD is **y=-X+-2** -X+Y > The opposite reciprocal of the slope of AD 0=-1(-2) > -2 is the X value for the midpoint and 0 is the Y value for the midpoint for AD 0= +2 +C -2 -2 +C -2=C The perpendicular bisector is **3/5X-1.4** 0=3/5X+Y >The opposite reciprocal of the slope of DG -.5=-3/5(1.5)+C ---> 1.5 is the X value and .5 is the Y value for the midpoint for DG -.5=-.9+C +.9 +.9 -1.4=C

-1X-2=3/5X-1.4 System of equations +X +X to get all the variables on one side -2=8/5X-1.4 +1.4 +1.4 to get all the numbers on a side __-.6=8/5X__ 8/5 8/5 Divided 8/5 to get X alone X=-3/8 The X value for the circumcenter

To find the Y you put the X value (-3/8) into one of the slope equations -1(-3/8)-2 3/8-2 Y=-13/8 This is the Y value for the Circumcenter To find the distance of the radius: -4+3/8=3.625 3.625 x 3.625=13.140625 to square the number -1.625+2= .375 .375 x .375 = .140625 to sqaure the number .140625+ 13.140625= 13.28125 Then we would find the sqaure root of 13.28125 which equal **3.644 (The radius' distance)**
 * (-3/8, -13/8) is the circumcenter**