BOYS+HAVE+COOTIES+BUT+SO+DOES+DARCIE!!

Sarah G Darcie D Hour 7 =Number 1)=

This is the triangle that we are going to perform various activities on. It is an acute triangle as you can see from the angle measures that are under 90 degrees. It also is a scalene triangle as well because as you can see the angles aren't the same meaning any segment is also not congruent.

=Number 2)=

For our triangle, we calculated the midpoints of line segment BC to be (-4.5, .5) which is point D and line segment AB's midpoint to be (-2.5, 4.5) which is point E. For the midpoint of line segment BC, we took the cordinates of B (-6, 3) and C (-3,-2) and added the x values and the y values then divided by two. Using the same method to figure out the midpoint of line segment AB, the cordinates A (1, 6) and B (-6, 3) were used to get us the midpoint. = Number 3) = We then came up with the slopes of the two sides of the triangles, AB and BC. To calculate the slope of AB we subtracted the coordinates of B to A: (-6, 3) - (1, 6) = -7, -3 and then flipped -3 to the top of the fraction, making it -3/-7 but changing the slope to positives, 3/7 was our slope for BA. For slope BC, doing the same equation: (-6, 3) - (-3, -2) = -3, 5 which gave us 5/-3 as our fraction.

To get the perpendicular bisector equation of side AB, we took the slope 3/7 and turned it into its opposite recipicol, -7/3. Taking point E (-2.5, 4.5) and -7/3, we fixed the numbers into the formula y=mx+b, making it 4.5= -7/3 (2.5) + b. Once we figured out the equation, -1.33 was the value of b. So the perpendicular bisector equation of side AB is y= -7/3x - 1.33 To get the perpendicular bisector equation of side BC, we took the slope 5/-3 and turned it into its opposite recipicol, 3/5. We took point D (-4.5, .5) and 3/5 and fixed them into the formula y=xm+b, making it .5= 3/5 (-4.5) + b. Once we figured out the equation, 3.2 was the value of b, making the perpendicular bisector equation of side BC: y= 3/5x + 3.2

=Number 4 & 5)=

This is the work for the system of the equations, the coordinates of the F point (circumcenter), and the radius of the circumscribing circle.